4x^2-19x+29=0

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Solution for 4x^2-19x+29=0 equation: 



4x^2-19x+29=0

a = 4; b = -19; c = +29;
Δ = b2-4ac
Δ = -192-4·4·29
Δ = -103
Delta is less than zero, so there is no solution for the equation

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